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Mathematics 12 Online
Parth (parthkohli):

Encountered a bunch of impossible questions related to straight lines.

TheSmartOne (thesmartone):

Example?

Parth (parthkohli):

I just felt like sharing them, so... coming up right in a second.

TheSmartOne (thesmartone):

How you are the Honorary Professor of Mathematics?

TheSmartOne (thesmartone):

When in doubt, tag @satellite73 :D

OpenStudy (igreen):

@TheSmartOne He has 5,800 medals in Mathematics.

TheSmartOne (thesmartone):

If Parth can't do it, then I must try...

Parth (parthkohli):

I solved them, but the questions were pretty nice. So... - A variable line makes intercepts on coordinate axes, the sum of whose squares is constant and is \(k^2\). Find the locus of the perpendicular drawn from origin to the line. - A rectangle PQRS has its side PQ parallel to the line \(y = mx\) and vertices P, Q, S on the sides \(y = a\), \(x = b\), \(x = -b\). Find the locus of R. - P is any point on the line \(x- a = 0\). If A is the point \((a,0)\) and PQ, the bisector of \(\rm \angle OPA\), meets x-axis on Q, then find the locus of the foot of the perpendicular from Q on OP.

Parth (parthkohli):

Enjoy.

TheSmartOne (thesmartone):

I give up...

OpenStudy (solomonzelman):

if you post all impossible question lol, well .... you know you won't. You won't ever finish typing :)

Parth (parthkohli):

@dan815 Try this.

OpenStudy (dan815):

uhh wat is a locus of the perpendicular mean again

Parth (parthkohli):

A locus of a moving point is the path that the point takes when it moves. The locus here is not of the perpendicular, but of the foot of the perpendicular, which is the point where your perpendicular lands.

hartnn (hartnn):

If you solved it, it ain't impossible :P

Parth (parthkohli):

Considering that it at least took five attempts for all of those questions, they're effectively impossible.

OpenStudy (dan815):

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