suppose you roll two dice. find the probability of rolling a sum of 9.
we need to count how many ways you can get a total of 9 on two dice it is not that many, so we can list all of them
\[(4,5), (5,4), (6,3),(3,6)\] are the possible combinations that get a total of 9
so it would be 4?
nope, not quite, that is the numerator of our fraction
there are 4 ways to get a 9, and \(6\times 6=36\) possible rolls all together
the probability of getting the 9 is therefore \[\frac{4}{36}\] which you can reduce if you like
i can see if i can find you a table with all the rolls filled in, then these are pretty easy
not filled in but you can fill it in yourself just add up to get each entry in the 6 by 6 table
it said the answer was wrong, but it didn't give an explanation as to why.
maybe it wanted it reduced to \(\frac{1}{9}\) ?
did you put in 4/36?
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