Question

how many atoms are in 8.70 mol of copper (II) Phosphate

Answer 1

The formula of copper (II) phosphate is \(\sf Cu_3(PO_4)_2\).

As you know, 1 mole of any substance consists of \(\sf 6.022×10^{23}\) molecules. From here, you can calculate number of \(\sf Cu_3(PO_4)_2\) molecules in 8.70 moles.
\(8.70\times 6.022 \times10^{23}\approx 5.24\times 10^{24}\) molecules

Next, from the formula \(\sf Cu_3(PO_4)_2\), you can easily find the number of atoms:
\(3+2\times (1+4)=13\).

Therefore, the number of atoms is \(\sf 13\times 5.24\times 10^{24}\approx 6.81\times 10^{25}\) atoms