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Geometry 16 Online
OpenStudy (anonymous):

Use the Distance Formula and the x-axis of the coordinate plane. Show why the distance between two points on a number line (the x-axis) is | a – b |, where a and b are the x-coordinates of the points.  

OpenStudy (anonymous):

okay, so do you know what the distance formula is?

OpenStudy (anonymous):

Since we know the points are on the \(x\) axis, then their \(y\)-coordinates must be \(0\).

OpenStudy (anonymous):

So we need to show the distance between \((a,0)\) and \((b,0)\) equals \(|a-b|\).

OpenStudy (anonymous):

Yes, I'm just not entirely sure how to do that

OpenStudy (anonymous):

Okay, what is the distance formula?

OpenStudy (anonymous):

The distance between the given points?

OpenStudy (anonymous):

I mean, do you know the formula for finding the distance between two points?

OpenStudy (anonymous):

No, that's what I need help with.

OpenStudy (anonymous):

Okay, if you have two points \((x_1,y_1)\) and \((x_2,y_2)\) then the distance between them is given by: \[ |(x_1,y_1)(x_2,y_2)|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \]

OpenStudy (anonymous):

In our case, we end up with: \[ \sqrt{(b-a)^2+(0-0)^2} \]

OpenStudy (anonymous):

Can you simplify this?

OpenStudy (anonymous):

b-a?

OpenStudy (anonymous):

Can you show your work?

OpenStudy (anonymous):

\[ x_2=b\quad\text{and}\quad x_1=a \]

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