Choose the equivalent system of linear equations that will produce the same solution as the one given below. 6x + 2y = -6 3x - 4y = -18
can anyone help
First off, try solving it and then tweak the variables a little with some algebraic properties so we get a new, but equivalent system of linear equations.
how do i solve this
ill come back when your finished writing brb
Okay, let's first look at the system of equation, I'll take the 1st equation and solve for one variable: \[6x+2y=-6\] \[2y=-6-6x\] \[y=\frac{ -6x-6 }{ 2 }\] \[y=\frac{ 6(-x-1) }{ 2 }=3(-x-1)=-3x-3\] \[y=-3x-3\] After solving for the variable I chose, I'll replace it on the 2nd equation: \[3x-4y=-18\] \[y=-3x-3\] then: \[3x-4(-3x-3)=-18\] \[3x+12x+12=-18\] \[15x=-30\] \[x=\frac{ -30 }{ 15 }\] \[x=-2\] having found "x", all we have to do is replace it on the "y" value we had found on the first equation: \[y=-3x-3\] \[x=-2\] then: \[y=-3(-2)-3\] \[y=6-3=2\] \[y=2\] and thus, solving the problem.
ok
can i show you the list of answers though
here look
Choose the equivalent system of linear equations that will produce the same solution as the one given below. 6x + 2y = -6 3x - 4y = -18 ANSWERS BELOW!!! ___________________ A. 12x + 4y = -12 15x = -30 B. 8x + 4y = -4 14x = -10 C. 6x - 8y = -36 -6y = -42 D. 6x - y = -15 3y = 9
there
@ganeshie8
how to solve
@ganeshie8 you there
6x + 2y = -6 3x - 4y = -18
what
multiply first equation by 2 you get 12x + 4y = -12 3x - 4y = -18 yes ?
yeah
next add both the equations vertically
ok
do it
ok wait how exatly
ok nvm then.
12x + 4y = -12 3x - 4y = -18 -------------------- 15x + 0 = -30
oh
ok
you just add them column by column like above ^
ok thanks i get it now
you're welcome!
oh, Sorry if I didin't response, I lost connection X.x
oh
anyways bye guys im going to close the question now
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