Question

Please do this for me D': i'LL GIVE A medal, testimonial and a follow in return. x

Answer 1

@mathmate

Answer 2

@mathmath333

Answer 3

Hints:
1. Factorize the numerator to (x-1)(x+5).
2. recognize that the denominator is zero when x=5, which means that the value must be excluded from the domain.
3. parts 3 and 4 will need a calculator and pencils once parts 1 and 2 are solved.

Answer 4

I know how to get an answer, I just don't have the steps to get there. so if I tell you the answers, could you show me the steps?

Answer 5

@mathmate

Answer 6

1.
\(\large\tt \begin{align} \color{black}{c(x)=\dfrac{x^2+4x-5}{x+5}\\~\\
c(x)=\dfrac{(x+5)(x-1)}{x+5}\\~\\

}\end{align}\)
we can't cancel \( (x+5) \)if \(x=-5\)
so
domain=\(\large\tt \begin{align} \color{black}{\{x:x\in \mathbb{R}:x\neq -5\}}\end{align}\)