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Mathematics 21 Online
OpenStudy (anonymous):

If you do this, I would give you a medal, a follow, and a testimony. Also, a shoutout on instagram from my poetry account (@herbrokenpoetri) which has like 7k followers. So uhm, please?

OpenStudy (anonymous):

OpenStudy (nikato):

restricted values for x are values of x that make the denominator 0 so set the denominotr for 0 and solve for x x+5=0 x=?

OpenStudy (anonymous):

once you get done factor and cancel

OpenStudy (anonymous):

5?

OpenStudy (anonymous):

so domain is 5?

OpenStudy (nikato):

5 is what the domain cant be. it makes your answer undefined

OpenStudy (anonymous):

so how do I get there?

OpenStudy (anonymous):

oh no set \[x+5=0\] solve for \(x\) you do not get \\(x=5\) you get \(x=-5\) so the domain is all numbers EXCEPT \(-5\)

OpenStudy (anonymous):

then factor and cancel

OpenStudy (anonymous):

How about for b?

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

@Compassionate

jimthompson5910 (jim_thompson5910):

are you able to evaluate c(-6) ?

OpenStudy (anonymous):

nope :-(

jimthompson5910 (jim_thompson5910):

to find the value of c(-6), you replace every x in c(x) with -6 then you evaluate

jimthompson5910 (jim_thompson5910):

\[\Large c(x) = \frac{x^2+4x-5}{x+5}\] \[\Large c(-6) = \frac{(-6)^2+4(-6)-5}{-6+5}\] \[\Large c(-6) = \ ???\]

OpenStudy (anonymous):

Uhm... 36 +20-5?

jimthompson5910 (jim_thompson5910):

36 - 24 - 5 = ??

OpenStudy (anonymous):

7

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

I'm getting -7

jimthompson5910 (jim_thompson5910):

double check to make sure you didn't lose a negative sign somewhere

OpenStudy (anonymous):

Oh sorry, that's what I got i just didn't put the negative :/

jimthompson5910 (jim_thompson5910):

oh ok

jimthompson5910 (jim_thompson5910):

so -7 goes under the -6

jimthompson5910 (jim_thompson5910):

the -7 goes in the c(x) row

jimthompson5910 (jim_thompson5910):

what is c(-5) ?

OpenStudy (anonymous):

what do you mean?

jimthompson5910 (jim_thompson5910):

plug x = -5 into the c(x) function what do you get?

OpenStudy (anonymous):

but why do I plug that in?

jimthompson5910 (jim_thompson5910):

because you're making the table for x = -6 through x = 2

OpenStudy (anonymous):

i get a -35

OpenStudy (anonymous):

I need to turn this in tomorrow and it's already nine D: and I have to help my parents with some work today too .

jimthompson5910 (jim_thompson5910):

you should get undefined since x+5 = -5+5 = 0 is in the denominator

OpenStudy (anonymous):

Wait...s o it's supposed to be 0? I got 0 for the bottom part

jimthompson5910 (jim_thompson5910):

yeah if you have 0 in the denominator, then you have an undefined expression

OpenStudy (anonymous):

Ohh

OpenStudy (anonymous):

So for the chart ... what do you I put? and for b?

jimthompson5910 (jim_thompson5910):

oh the table is for part c), my bad

jimthompson5910 (jim_thompson5910):

for part b, try to factor the numerator

jimthompson5910 (jim_thompson5910):

what do you get when you do so?

OpenStudy (anonymous):

What does it mean to factor the numerator?

jimthompson5910 (jim_thompson5910):

are you able to factor x^2 + 4x - 5 ?

OpenStudy (anonymous):

is it -1?

jimthompson5910 (jim_thompson5910):

x^2 + 4x - 5 factors to (x + 5)(x - 1)

jimthompson5910 (jim_thompson5910):

hopefully you see what cancels

OpenStudy (anonymous):

the x?

jimthompson5910 (jim_thompson5910):

no, the x+5 terms cancel

jimthompson5910 (jim_thompson5910):

in the numerator and denominator

OpenStudy (anonymous):

So that's the answer. x=-1?

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

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