Algebra plz help suppose y varies directly with x. Write a direct variation equation that relates x and y. Then find the value of y when x=12. y=-10 when x=2
a direct relationship means that as y increases, x increases as well when multiplied by a constant k. On the contrary, an inverse relationship is when y increases and x decreases, vise versa.
ok I'm with you so far
direct variation: \( y = kx\) indirect variation: \(y = \dfrac{k}{x}\)
We take our equation for direct variation, \(y=kx\) and solve for \(k\) first.\[k = \frac{y}{x}\] We can solve for the second part of the problem first when x = 2, y = -10.
Plug those values in for the equation for k, and tell me what you get :)
ok give me a second :)
-10=k2
"2k"?
Oh no no. solve for \[k= \frac{-10}{2}\]
oh ok sorry
No problem :)
k=-5
Good. Now that we've got our value for k, we can revert back to our original euation, \(y=kx\) and solve for \(y\) when \(x=12\) and \(k=-5\) \[y=kx\]\[y = (-5)(12) = ~?\]
-60
Good job :)
thank you so much i understand how to do these now
Woo!
:D
hey can you help me with one more thing?
Hmm. I can try :)
You can close this question and post up a new question :)
That way you wont be spamming one question with multiple questions, haha
ok
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