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Mathematics 20 Online
OpenStudy (anonymous):

If there are 24 ways to arrange the letters A,B,C,D: a. How many derangements are there? (23?) b. How many have exactly 1 letter in the correct place? (9?) c. 2 letters? (4?) d. 3 letters? (0?) e. 4 letters? (1?) f. No letters? (9?) g. What is the sum of the answers to b-f? (23?) h. What have and question number is the answer in question g equal to?

OpenStudy (anonymous):

This is what I have

OpenStudy (wolf1728):

Do you have to list all 9 derangements of ABCD?

OpenStudy (anonymous):

Yep. Duh! I was thinking arrangements the whole time (it's the wording of the questions I think. But still not sure about the answers I am getting.

OpenStudy (wolf1728):

Let's try that again BADC BCDA BDAC CADB CDAB CDBA DABC DCAB DCBA

OpenStudy (anonymous):

Got that.

OpenStudy (anonymous):

The subsequent questions are asking how many of the ARRANGEMENTS have exactly______ in the correct place?

OpenStudy (wolf1728):

Okay - well you got it again LOL Okay so just the first part of the question has to due with derangements. The rest refer to arrangements.

OpenStudy (anonymous):

Right.

OpenStudy (anonymous):

I am showing 7 arrangements with exactly one letter in correct place now.

OpenStudy (anonymous):

4 with exactly 2 in correct order

OpenStudy (wolf1728):

I'm working on showing all 24 arrangements of ABCD I think that will help

OpenStudy (anonymous):

I attached those in a picture earlier. It was just missing ABCD

OpenStudy (wolf1728):

Oh gee, well here they are A B C D A B D C A C B D A C D B A D B C A D C B B A C D B A D C B C A D B C D A B D A C B D C A C A B D C A D B C B A D C B D A C D A B C D B A D A B C D A C B D B A C D B C A D C B A D C A B Okay I'll look for how many are in the correct oreder.

OpenStudy (anonymous):

Okay, I think I have all the correct orders right now and the sum of the =24.

OpenStudy (wolf1728):

I count 8 with exactly 1 letter in the correct place A C B D A D C B B C A D B D C A C A B D C B A D D A C B D B A C

OpenStudy (anonymous):

That's what I have.

OpenStudy (anonymous):

6 with exactly 2

OpenStudy (anonymous):

None with exactly 3

OpenStudy (anonymous):

1 with exactly 4

OpenStudy (anonymous):

And then the 9 with none.

OpenStudy (wolf1728):

Hmmmmmmm looks like the first one A C B D is wrong - that has 2 in the correct place

OpenStudy (wolf1728):

Second one also has 2 letters in correct place ARRGGHHH !!!!!!!!!!!!!!!!!!!!!

OpenStudy (anonymous):

Yeah, I did that the first time also. But I still had 8 with one

OpenStudy (anonymous):

ACDB ADBC BCAD BDCA CADB CBDA DACB DBAC

OpenStudy (perl):

what is the difference between a derangement and an arrangement?

OpenStudy (perl):

(im just curious)

OpenStudy (anonymous):

A derangement has no object in its correct place.

OpenStudy (perl):

oh

OpenStudy (anonymous):

An arrangement could have one or more in the correct place

OpenStudy (perl):

so you can count these by no letters in the right place 1 letter in the right place 2 letters in the right place 3 letters in the right place 4 letters in the right place

OpenStudy (perl):

arrangements are 1 or more letters in the incorrect place

OpenStudy (anonymous):

Right. However, In this case, you won't have any with 3 letters in the correct place. Since there are four letters, if three are in correct places, then all four are in the correct place.

OpenStudy (anonymous):

An arrangement can also have all values (letters) in the correct place.

OpenStudy (perl):

good point :)

OpenStudy (wolf1728):

Derangements - NO letters in correct place 9 1 letter in correct place 9 2 letters in correct place 5 4 letters in correct place 1

OpenStudy (anonymous):

Hmmmmm, on my second and third count, I got 8 and 6. :/

OpenStudy (wolf1728):

Yes I think 8 and 6 is correct

OpenStudy (wolf1728):

As far as derangements there is a formula so I know that number is correct: http://www.1728.org/derange.htm As far as 1 number and 2 numbers, I'm sure there must be a formula but I'm not familiar with it.

OpenStudy (anonymous):

The sum would be 24 of course.

OpenStudy (wolf1728):

bcurley Do you need the actual arrangements for 1 letter and 2 letters? (I have those on a separate spreadsheet and it would be VERY EASY to copy and paste.)

OpenStudy (anonymous):

So now where I am stuck is the question that says "What value and question number (letter) in the answer in "g" equal to?"

OpenStudy (anonymous):

No, no need to list the different variations. Just asks how many.

OpenStudy (wolf1728):

Okay - as far as the total (I can't see ALL the questions) I imagine the answer is the sum of the derangements, 1 letter 2 letter, etc would equal the total number of arrangements. 24

OpenStudy (anonymous):

Hang on...

OpenStudy (anonymous):

This shows all the questions as written on the paper.

OpenStudy (wolf1728):

Okay it is what I said. The answers to all those questions about the derangements, 1 letter in correct place, etc would equal ALL possible arragements.

OpenStudy (anonymous):

She did give us the hint of (Sum). Took me a minute to realize that.

OpenStudy (wolf1728):

Okay - then I guess we are all set. :-) Okay see ya.

OpenStudy (anonymous):

Thanks. I appreciate it.

OpenStudy (wolf1728):

u r welcome :-)

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