Question

Express 5/3-radical 2 with a rational denominator in the simplest radical form

Answer 1

@satellite73

Answer 2

@sammixboo

Answer 3

@Directrix

Answer 4

5 divided by 3-radical 2

Answer 5

5 is the numerator, 3- radical 2 on denominator

Answer 6

\[\frac{5}{3-\sqrt{2}}\]

Answer 7

Since there is a radical in the denominator, you need to take the conjugate of the function on the bottom, that is, if you have \(a+b\) then it's conjugate would be \(a-b\)

Answer 8

so i multiply by conjugate

Answer 9

would that be 3+2i?

Answer 10

@ganeshie8

Answer 11

no, it's not complex.

Answer 12

This is what you do: \[\frac{5}{3-\sqrt{2}}\cdot \frac{3+\sqrt{2}}{3+\sqrt{2}}\]\[= \frac{5(3+\sqrt{2}}{3^2 - (\sqrt{2})^2}\]NOw simplify this.

Answer 13

Meant to write \(5(3+\sqrt{2})\) on top.