Question

What is the equation of y = x3 with the given transformations?
vertical compression by a factor of 1 over 7, horizontal shift 8 units to the left, reflection across the x-axis

Answer 1

@ganeshie8 I know this is simple, but I'm so confused. Would you mind helping?

Answer 2

y = f(x)

verticall compression by a factor of c : y = c*f(x)
horizontal shift k units to the left : y = c*f(x+k)
reflection across x axis : y = -c*f(x+k)

Answer 3

@ganeshie8 just curious how do you write your quadratic in vertex form?

Answer 4

Y=-1/7(x^3+8) @ganeshie8 ?

Answer 5

@triciaal are you asking what vertex form is?

Answer 6

not quite

Answer 7

no
f(x) = a(x-h)^2 + k

Answer 8

y = x^3

verticall compression by a factor of 1/7 : y = (1/7)*f(x)
horizontal shift 8 units to the left : y = (1/7)*(x+8)^3
reflection across x axis : y = -(1/7)*(x+8)^3

Answer 9

@triciaal quadratic ?

Answer 10

Okay. So f(x) wasn't an example XD I understand now.. Thank you.

Answer 11

good.

f(x) = x^3

f(x+k) = (x+k)^3

Answer 12

you just replace "x" by "x+k"

Answer 13

@ganeshie8 oh because it's a cube function

Answer 14

but the transformation results are the same

Answer 15

Thank you, ganeshie.

Answer 16

thanks