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OpenStudy (sagewilson):
OpenStudy (jhannybean):
Remember SOHCAHTOA?
Which identity (SOH CAH TOA) relates adjacent sides with the hypotenuse?
OpenStudy (sagewilson):
it's cah
OpenStudy (jhannybean):
Good!
OpenStudy (jhannybean):
\[\cos(\theta) = \frac{adj}{hyp} = \frac{14}{26}\]REmember what I told you about finding the ange?
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OpenStudy (jhannybean):
angle*
OpenStudy (sagewilson):
you said to find the adjacent and hypothnuse. right?
OpenStudy (jhannybean):
mmhmm, and what would they be?
OpenStudy (sagewilson):
hyp - 26 adj - 14
OpenStudy (jhannybean):
Yes, exactly what I have posted above too :) Good.
Do you remember what I said to do next?
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OpenStudy (nurali):
\[\theta=\cos ^{-1}(\frac{ 14 }{ 26 })\]
OpenStudy (jhannybean):
<_<
OpenStudy (sagewilson):
x3 i believe you said to simplify it
OpenStudy (jhannybean):
Yeah :) plug the function @Nurali stated into your calculator using degrees andnot radians.
OpenStudy (sagewilson):
ok
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OpenStudy (jhannybean):
But what I had said to do in the ast problem we worked on was to the the inverse functions of both sides, that way you could derive the \(\theta\) value
OpenStudy (sagewilson):
alright
OpenStudy (sagewilson):
I ended up getting an answer that's not on there, would it end up being choice 4?
OpenStudy (jhannybean):
Im finding the angle fine.
OpenStudy (jhannybean):
are you using a scientific calculator?
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