Probability theory predicts that there is 77.6% chance of a particular soccer player making 2 penalty shots in a row. If the soccer player taking 2 penalty shots is simulated 2500 times, in about how many simulations would you expect at least 1 missed shot?

Question

perl · Answer

do you need help with this

perl · Answer

be right back

hockeychick23 · Answer

ok and yep i do thanks

perl · Answer

Probability theory predicts that there is 77.6% chance of a particular soccer player making 2 penalty shots in a row. If the soccer player taking 2 penalty shots is simulated 2500 times, in about how many simulations would you expect at least 1 missed shot?

First off , lets get probability. we can use the complement 

P ( at least 1 missed shot ) = 1 - P ( no missed shots)

hockeychick23 · Answer

ok so its p^2= .776 and p=.88090862182

hockeychick23 · Answer

oh i did something wrong then sorry

perl · Answer

P ( at least 1 missed shot ) = 1 - P ( no missed shots)
= 1 - .776

perl · Answer

i think you solved for p, which is another way to do it

perl · Answer

but it might be harder approach

hockeychick23 · Answer

oh ok then, i got p=.224 now

perl · Answer

right

perl · Answer

now you can multiply that probability by the total population

hockeychick23 · Answer

ok .224(2500)= 560

perl · Answer

correct

hockeychick23 · Answer

oh wow that was actually a lot quicker of a problem than i thought, thanks so much!