solve the quadratic equation by completing the square -3x^2+9x=1

Question

hartnn · Answer

what have you tried ?
I would have started by dividing the entire equation by -3

anonymous · Answer

I don't understand how to solve it...

anonymous · Answer

that's what I need help understanding

hartnn · Answer

you need to complete the square on left side

like for
$x^2+2bx$

you will add b^2 to make it
$x^2+ 2bx+b^2 $

which indeed is a perfect square : $(x+b)^2$

hartnn · Answer

so for 
-3x^2 +9x =1
first divide entire equation by -3
to make the co-efficient of x^2 as 1 

then we will start completing the square

anonymous · Answer

so by dividing the whole thing by -3 x^2 becomes 1?

anonymous · Answer

1x^2 +-3x

hartnn · Answer

the 'co-efficient' of x^2 will become 1, right ?
as 
-3x^2/-3 = x^2

anonymous · Answer

ok

anonymous · Answer

soooo, why is it = x^2

hartnn · Answer

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