Question

solve the quadratic equation by completing the square -3x^2+9x=1

Answer 1

what have you tried ?
I would have started by dividing the entire equation by -3

Answer 2

I don't understand how to solve it...

Answer 3

that's what I need help understanding

Answer 4

you need to complete the square on left side

like for
\(x^2+2bx\)

you will add b^2 to make it
\(x^2+ 2bx+b^2 \)

which indeed is a perfect square : \((x+b)^2\)

Answer 5

so for
-3x^2 +9x =1
first divide entire equation by -3
to make the co-efficient of x^2 as 1

then we will start completing the square

Answer 6

so by dividing the whole thing by -3 x^2 becomes 1?

Answer 7

1x^2 +-3x

Answer 8

the 'co-efficient' of x^2 will become 1, right ?
as
-3x^2/-3 = x^2

Answer 9

ok

Answer 10

soooo, why is it = x^2