A car enters an interstate highway 15 miles north of a city. The car travels north at an average speed of 62.5 mph. Which equation models the car's distance d from the city after traveling for h hours? A) 62.5 = 15h + d B) 15 = h + 62.5 C) d = 62.5h + 15 D) d = 15h + 62.5
@jalyssa_ar00
well you know that 62.5 is the rate at which the distance is changing every hour. and you're trying to find d so it's going to be be d equals. something
15 is your initial condition, since when the car started it was already 15 away
that's never going to change so it wouldn't make sense for it to give it a variable.
since h can be anything you'll just leave it as h
So.. the correct answer would be D ?
no, because 15 is your starting point and that never changes regardless of h
Okay so C would be correct?
yes
Thanks so much. Could you help me with a few more?
sure, if i can.
An empty 5-gal water jug weighs 0.75 lb. With 3 c of water inside, the jug weighs 2.25 lb. Which equation models the jug's weight y when it contains x cups of water? A) y = 2x + 0.75 B) y = 0.5x + 0.75 C) y = -x + 3 D) y = -0.167x + 2.25
well we know that 0.75 is our constant. since the jug by itself always weighs that much.
lets set up an equation using the givens. \[2.25 = w(3) + 0.75\]
i used w to signify the rate at which it changes depending on the number of cups.
alright so when you solve for w what do you get?
0.75 times 3 equals 2.25 but I'm not sure if that's what you were asking
Okay so do you understand how i got that equation?
Yes. Would the answer be B ?
yes.
Thank you so much. :)
No problem, I'm glad to help.
Could you help me with a few more?
sure.
A concession stand vendor counts the money in the register. After 2 h, it has $82.75. After 6 h, it has $360.75. How much money will be in the register at the end of an 8-hour shift? A) $480.00 B) $489.25 C) $499.75 D) $500.00
okay so what we're going to have to do here is use some subsitution.
the equation to model this will be: y = mx + b y is amount m is rate per hour x is hour b is how much you started with
I messed up. I put A & It was incorrect.
so using what we're given you get two equations: 82.75 = m(2) + b and 360.75 = m(6) + b
we can't solve for 2 variables at once so we'll solve for one in terms of the other. So we'll start by converting the first one in terms of b
Could we skip this one & go to the next one?
sure.
The cost of producing 4 metal units is $204.80. The cost of producing 8 units is $209.60. What is the cost to produce 12 units? A) $212.80 B) $214.00 C) $214.40 D) $216.80
I think it would be B but I'm not sure...
this is similar, since we don't know the initial cost. so with the y = mx + b: we get 204.80 = 4m + b and 209.60 = 8m + b
let's but the first one in terms of b since that's easier. so subtract 4m from both sides: 204.80 - 4m = b
the 4m on the right side is gone since 4m - 4m is 0 now that we have this equation for b we can plug it into the second equation for b
so now we get 209.60 = 8m + (204.80 - 4m)
since the m's have the same variable we subtract them and get 209.60 = 204.80 + 4m
subtract 204.80 from both sides gets you: 209.60 - 204.80 = 204.80 - 204.80 + 4m 4.80 = 4m
divide by 4 and m is 1.20
now we know m = 1.20 so we'll plug it into the other equation 204.80 - 4m = b 204.80 - (4 * 1.20) = b
204.80 - 4.80 = b b = 200
so now you have your equation that you can plug a value into: y = 1.20x + 200
so for 12 units you get y = 1.20(12) + 200
which becomes y = 14.40 + 200
So the correct answer would be $214.40 ?
Yup, you've got it.
Thank you for explaining that to me :)
No problem.
Could you help with 1 more?
sure
Look at the scatter plot. Which of these equations is the best representation of the trend line? A) y = 4x + 2 B) y = 1/4x + 2 C) y = -1/4x + 2 D) y = 1/4x - 2
Do you have a picture of the scatter plot?
It wont let me get the photo of it.
But the scatter plot shows the line going through 4 dots with 3 dots above the line & 2 below the line.
are there number values on it?
It's just a basic y coordinate, x coordinate graph with the numbers on the left side.
|dw:1417829164725:dw| something like this
?
No, one sec..
|dw:1417840271249:dw|
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