Question

A box of weight 135 N is attached to the end of a dangling spring, stretching the spring by 21.0 cm. What is the weight of an object that would stretch the spring by 69.6 cm?

Answer 1

Springs are governed by: F = -kx

Use the first sentence of information to solve for 'k'.

Then plug in that value of 'k' with the second sentence's distance 'x' to get an 'F'. This force would be the force needed to stretch the spring the given distance. Weight is a force, so the weight would be this value.

Answer 2

21 divided by 135?

Answer 3

10.827?

Answer 4

Wait a sec, 21/135.. no no, 135/21
k = F/x

Answer 5

i got 447 N

Answer 6

F = 447.4 [kg cm / s^2] converted to Newtons by multiplying 0.01 [m / cm]

F = 4.474 N

Answer 7

thanks! I got it now