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how do you find the avg of a function over a given interval when given something like f(x)=x^4-x with intervals like [0,3]
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Give me 5 minutes. I can answer this.
Ok, look the formula for a question like this is |dw:1417841024259:dw|
SO your interval is 0,3. You plug 0 and 3 into the original equation.
|dw:1417841147178:dw| so the avg would be 27.
I let B represent 3 here and A represent 0
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\[\frac{1}{b-a}\int\limits_{a}^{b}f(x) dx\]
thank you @dtan5457
@sourwing I got 14.7
correct
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I used that formula..so..
Actually, only mistake I see I did is that it's suppose to be 78-0 divided by 3. the avg is 26, I forgot to subtract x for F o 3.
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