Let a,b,c be positive integers such that ab+bc-ca=0 and a-c=523. Find b.
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ganeshie8 (ganeshie8):
what have you tried ?
OpenStudy (anonymous):
so this is a diff eq problem?
OpenStudy (anonymous):
set c= 523 plug them all in and try to find the answer
OpenStudy (mathmate):
@hzer I read \(a-c=523\)
OpenStudy (anonymous):
ok then what
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OpenStudy (anonymous):
well ok that is ok but also if you plug all of them in it will not give you the right one don't you think so mathmate
hartnn (hartnn):
this could be a start :
\(\Large \dfrac{1}{b}=\dfrac{1}{a}+\dfrac{1}{c}\)
hartnn (hartnn):
b= c(c+523)/(2c+523)
hartnn (hartnn):
for b to be a positive integer
2c+523 should divide c (c+523)
OpenStudy (mathmate):
@hartnn
I solved for c in c(c+523)/(2c+523)\(\in\) N [but by brute force]:
a=137026=2*131*523
b=68382=2*3^2*29*131
c=136503=3^2*29*523
and
1/b=1/a+1/c
ab+bc-ca=0
...and there could be other solutions.
I wish I knew how to solve for c "mathematically".