Let a,b,c be positive integers such that ab+bc-ca=0 and a-c=523. Find b.
what have you tried ?
so this is a diff eq problem?
set c= 523 plug them all in and try to find the answer
@hzer I read \(a-c=523\)
ok then what
well ok that is ok but also if you plug all of them in it will not give you the right one don't you think so mathmate
this could be a start : \(\Large \dfrac{1}{b}=\dfrac{1}{a}+\dfrac{1}{c}\)
b= c(c+523)/(2c+523)
for b to be a positive integer 2c+523 should divide c (c+523)
@hartnn I solved for c in c(c+523)/(2c+523)\(\in\) N [but by brute force]: a=137026=2*131*523 b=68382=2*3^2*29*131 c=136503=3^2*29*523 and 1/b=1/a+1/c ab+bc-ca=0 ...and there could be other solutions. I wish I knew how to solve for c "mathematically".
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