Q: It takes 6400 years for one gram of radium to decay away to only 1/16 (one-sixteenth) of a gram. The half-life of radium is "1600" years on my HW, but wouldn't it be 800, its 1/16 is 6400 years, 1/8 left is 3200 years, 1/4 left is 1600 years and 1/2 after 800 years but my hw is saying its 1/2 life is 1600. it seems wrong...
decay law is: \[N(t)=N _{0}e ^{-t/\tau} \] tau is half-life
N(t) is number of radio-isotopes at time t, N_0 is number of radioisotopes at initial time, namely t=0 sec
please note that, sample mass m, is equals to: \[m=\frac{ \mu N }{ N _{A} }\] where mu is the uranium atomic mass, and N_A is the Avogadro number. similarly, we can write: \[m _{0}=\frac{ \mu N _{0} }{ N _{A} }\] inserting in the above formula, we can get: \[m=m _{0}e ^{-t/\tau} \]
sorry, not uranium, but radium
please substitute in above formula, as follows \[m=\frac{ m _{0} }{ 16 }\] then solve for t
1=0 yrs 0.5 =1600 0.25 =3200 0.125 = 4800 0.0625 = 6400 you missed out the 4800 step
in fact you halved the years, not the radiation....
thank you, i knew i was missing something/going about it wrong
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