Question

@ganeshie8 will award medal.

Answer 1

is this how i should set up my grid?

Answer 2

@hartnn

Answer 3

http://www.wolframalpha.com/input/?i=%5Csum%5Climits_%7Bi%3D0%7D%5E3%5Csum%5Climits_%7Bj%3D0%7D%5E3+%283%2B2*%28j*1%2F2%29%28i*3%2F4%29%29

Answer 4

http://www.wolframalpha.com/input/?i=%5Csum%5Climits_%7Bi%3D1%7D%5E4%5Csum%5Climits_%7Bj%3D1%7D%5E4+%283%2B2*%28j*1%2F2%29%28i*3%2F4%29%29

Answer 5

try 75 and 123

Answer 6

it didnt like em

Answer 7

make sure you enter 75 for lower bound and 123 for upper bound :P

Answer 8

yea i did and it said that they wernt correct

Answer 9

:(

Answer 10

k let me think then i hope you have unlimited attempts left ;)

Answer 11

oh yeaa, bebefits of calc II webwork

Answer 12

are upper bound and lower bound the same as upper sum and lower sum?

Answer 13

kindof..
but in some cases left sum can give you largest volume

Answer 14

right

Answer 15

for decreasing functions

Answer 16

can you try quick 28.125 and 46.125

Answer 17

better

Answer 18

;)

Answer 19

holy pellet, how did u do that?

Answer 20

i lost the area element before :O

Answer 21

could u possibly upload a photo of your work, or explain how to set it up?

Answer 22

that wolfram link is all i have but il try to explain

Answer 23

is it easily done freehand

Answer 24

volume using left sum : \[\sum\limits_{i=0}^3\sum\limits_{j=0}^3 \left(3+2*\frac{2j}{4} \frac{3i}{4}\right) \times \Delta A\]

\(\Delta A = \Delta x \times \Delta y = \dfrac{2}{4} \times \dfrac{3}{4}\)

Answer 25

why would both sums go to three? when x only goes to 2