Question

Given the curve how do I parametrize the tangent line at (2,1,8)?

Answer 1

Take derivative of the curve. Plug it into the formula of the tangent line at the point.

Answer 2

I know the derivative would be <1/(2radt),-4/t^2,t> but what would the formula be @Loser66

Answer 3

tangent line :
x =x0 + at
y = y0 + bt
z = z0+ ct, where <a, b, c> is derivative of the curve, <x0,y0,z0> is the point

Answer 4

should I be plugging something in for t? @Loser66

Answer 5

or you can use this formula, it works well also ;)
a(x-x0)+b(y-y0) +c(z-z0)=0

Answer 6

so would it be (1/2radt)(x-2)-4(y-1)/t^2+t(z-8)? @Loser66

Answer 7

I think so. :)

Answer 8

=0

Answer 9

alrite thank you :)