College Algebra: 3X3 Linear Systems! Can somebody work this out step-by-step with me? The problem is: "Stocks, Bonds, and a Mutual Fund: Marita invested a total of $25,000 in stocks, bonds, and a mutual fund. In one year she earned 8% on her stock investment, 10% on her bond investment, and 6% on her mutual fund, with a total return of $1,860. Unfortunately, the amount invested in the mutual fund was twice as large as the amount she invested in the bonds. How much did she invest in each?"
let x be money in stocks let y be money in bonds let z be money in mutual
I had the second equation right, but the first and third wrong. I set it that way.
where did you get z=2y?
x+y+z=25000 0,08*x+0.10*y+0.06*z=1860 z=2*(y)
he amount invested in the mutual fund was twice as large as the amount she invested in the bonds.
Ohhh, okay
So I plug 2y back into .08x+.10y+.6z=1860?
0.06*z
Yeah that's what I meant :D
plug z=2y into both equations x+y+z=25000 0,08*x+0.10*y+0.06*z=1860
you will have an 2 by 2 linear system then, you can solve that same was as yesterday then
you will have an 2 by 2 linear system then, you can solve that same wa* as yesterday then
i give up
spelling is too hard for me obviously
lolx it's okay Dan. So, my two linear systems are x+3y=25,000 and 0.08x+0.22y=1,860
haha, don't worry. Everyone gets better at it eventually
yes
Wouldn't I make x+3y=25,000 into 3y=25,000-x
Oh wait
wrong
I would make x+3y=25,000 into x=25,000-3y
both work
Let S represent the initial investment in Stocks. Let B represent the initial investment in Bonds. Let F represent the initial investment in Mutual Funds. S + B + F = 25000 .08S + .10B + .06F = 1860 F = 2B Those are your three equations in three unknowns. I don't know if you are supposed to solve those manually or if you are allowed to use technology. Using technology, you can see what the results are at: http://www.wolframalpha.com/input/?i=.08x+%2B+.10y+%2B+.06z+%3D+1860%2C+x+%2B+y+%2B+z+%3D+25000%2C+z+%3D+2y where x is Stocks, y is Bonds, and z if Mutual Funds @Natasha.g.2013 This problem can also be done with one equation but three equations were specified in the problem statement. Answered on your first post of the problem:
Well I plugged in x=25,000-3y into 0.08x+0.22y=1,860, solved it, and got y=7000
I agree. @Natasha.g.2013
Well, thank you for that Directrix, but I have to write everything out because I won't have a computer do my final exam.
I have the answers in the back of the textbook, but I want to know how to solve word problems step by step.
Thank you to everyone who helped. :)
np!
Join our real-time social learning platform and learn together with your friends!