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Mathematics 14 Online
OpenStudy (anonymous):

@ganeshie8 \[\huge \left(\begin{matrix}n+2 \\ 2\end{matrix}\right)\] does this evaluate to 2n+1

ganeshie8 (ganeshie8):

\[\dfrac{(n-2)!}{(n-4)!2!}\]

ganeshie8 (ganeshie8):

\[\dfrac{(n-2)(n-3)(n-4)!}{(n-4)!2!}\]

OpenStudy (anonymous):

(n-2)(n-3)/2!

ganeshie8 (ganeshie8):

yeah you get a square term

OpenStudy (anonymous):

it cannot be simplified firther right?

OpenStudy (anonymous):

further*

ganeshie8 (ganeshie8):

it can never become 2n+1 http://www.wolframalpha.com/input/?i=%28n-2%29+choose+2

OpenStudy (anonymous):

okay

ganeshie8 (ganeshie8):

hos did u get \(\binom{n-2}{2}\) ?

OpenStudy (anonymous):

there is a formula

OpenStudy (anonymous):

|dw:1417932170736:dw|

OpenStudy (anonymous):

k number of terms

ganeshie8 (ganeshie8):

for (a+b+c)^n that formula should give you \[\binom{n+3-1}{3-1}\]

ganeshie8 (ganeshie8):

which is same as \[\binom{n+2}{2}\]

ganeshie8 (ganeshie8):

right ?

OpenStudy (anonymous):

yes

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