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Physics 20 Online
OpenStudy (shrutipande9):

help me how you deduce the answer. what is the exact formula for this?

OpenStudy (shrutipande9):

OpenStudy (shrutipande9):

@Abhisar

OpenStudy (shrutipande9):

@iambatman to the rescue?

OpenStudy (shrutipande9):

is it just normal 4kw? i mean is there a formula if the bulbs r connected in series?

Parth (parthkohli):

Step 1: Find the power. Step 2: Find the energy.

Parth (parthkohli):

Also, you can safely eliminate b and c because they're not even units of energy.

OpenStudy (shrutipande9):

for each bulb it is 1kw....i m confused about the series thing

OpenStudy (shrutipande9):

ohh..yes..:P

OpenStudy (anonymous):

Oh ok, so do you know how the circuit looks like, you know the power formulas right?

OpenStudy (anonymous):

Is it in general you don't know what a series circuit is?

OpenStudy (shrutipande9):

yeah...lets suppose that...i hv forgot everything i know d basic formulas...

Parth (parthkohli):

\[P \propto V^2\]Now, when you connect four bulbs in series, then the voltage would get divided by 4 for each, and so the new power for each bulb would be the \(P/16\). Four bulbs would consume power \(P/16 \times 4 = P/4\). Here, \(P = 100 ~W\), so the power consumed by each is \(25 ~W\). Multiply that by 10 and you get \(E = 250 ~W\cdot h\).

OpenStudy (shrutipande9):

in series the voltage gets divided equally...cool...and when in parallel?

OpenStudy (anonymous):

In parallel circuits the components all have the same voltage

OpenStudy (abhisar):

In paralel the voltage is same for each ..

Parth (parthkohli):

What do you think? :)

OpenStudy (shrutipande9):

and how does p become directly proportional to v2? is there some logic behind it?

Parth (parthkohli):

\[P = V^2/R\]

OpenStudy (shrutipande9):

yeah...

OpenStudy (anonymous):

Here is a few things I guess you can remember for series and parallel circuits, |dw:1417936515962:dw| each component in a series circuit has the same current,

OpenStudy (shrutipande9):

ok so in series I remains constant. then y cant we use this formula...p=vi and as I is constant. p is directly proportional to v?

OpenStudy (shrutipande9):

Warning...I AM DUMB IN PHYSICS..:P

OpenStudy (anonymous):

Didn't mean to post that right away haha, went tab and it posted that but...\[R_{series} = R_1+R_2+R_3+...\]and if you know Kirchoff's Voltage Law it states "The sum of voltage changes going around complete circuit is zero" So if you take delta V1+delta V2 +...etc = 0 Resistor: always has a voltage drop Battery: V increases when +and decreases when - Parallel: |dw:1417936852292:dw| all the components have the same voltage \[\frac{ 1 }{ R_p } = \frac{ 1 }{ R_1 }+\frac{ 1 }{ R_2 }+\frac{ 1 }{ R_3 }+...\] and Kirchoff's current law here states I total = I1+I2+I3+...etc haha.

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