Find the exact value by using a half-angle identity. sin five pi divided by twelve
do you mean sin squared \[\sin ^{2}\left( \frac{ 5\Pi }{ 12 } \right)= .5\left( 1-\cos(2\left( \frac{ 5\Pi }{ 12 } \right) \right)\]
i think that is the way to go about it, sorry it took so long
first time using the equation tab
there is soposed to be another " ) " at the end but you get im sure
supposed
its not sin^2 its \[\sin \frac{ 5\pi }{ 12 }\] @briensmarandache
@campbell_st can you help?
\[\sin\frac{ 5\pi}{ 12} =(+ or -)\sqrt{\frac{ 1+\cos(\frac{ 5\pi }{ 12 } }{ 2}}\]
doesnt it have to be one half of the 5pi/12 because its the half angle identity
True
So 5pi/24
i think so... now what?
@swagmaster47 what do i do now?
Uhm
\[\sin(5\pi/12) = (+or-)\frac{ \sqrt{1-\cos(5\pi/6)}}{2}\] which equals
Since sine is positive in quadrant 1 \[\frac{ \sqrt{1+\sqrt(3)/(2)}}{2}\]
I used 5pi/6 as theta since it is an half angle problem
And 5pi/6 is in quadrant 1
my answers can be : \[1/2 \sqrt{2+\sqrt{3}}\] \[1/2 \sqrt{2-\sqrt{3}}\] \[\sqrt{2+\sqrt{3}}\] \[\sqrt{2-\sqrt{3}}\]
@swagmaster47
1st one
are you sure?
@SolomonZelman what do you think?
My interne cut out, here's my process \[\frac{ \sqrt{1+\sqrt(3)/(2)} }{ 2 } = \sqrt{2+\sqrt(3)/(4)} = 1/2 \sqrt{2 + \sqrt(3}\]
*internet
Join our real-time social learning platform and learn together with your friends!