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Can someone check my answers for this question? A basketball is dropped from an original height of 10 feet. On each consecutive bounce, it's height reaches 3/4 the previous height. What is the total distance the ball will have traveled between the original drop and the 4th bounce? Show all your work. Don't forget the units.
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\[S=\frac{ a1 }{(1-r)}\]\[S=\frac{ 7.5 }{ (1-.75) }\]\[S=30*2=60\]\[S=60+10\]\[S=70\]
1st bounce: 3/4 of 10 = 7.5 ft. 2nd bounce: 3/4 of 7.5 = 5.625 ft. 3rd bounce: 3/4 of 5.625 = 4.219 ft. 4th bounce: 3/4 of 4.219 = 3.164 ft.
That's... A lot easier than what I did. >-< Thank yhu...
Yw!
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