Question

How do you simplify nested radicals?

Answer 1

\[\sqrt[3]{3x/2 +\sqrt{x/4}}\]

Answer 2

does that help

Answer 3

holy molly

Answer 4

Pretty sure he pulled it off somewhere

Answer 5

Lolol do u have the link to it?

Answer 6

Yeah. http://2000clicks.com/mathhelp/BasicSimplifyingNestedRadicals.aspx

Answer 7

http://2000clicks.com/MathHelp/BasicSimplifyingNestedRadicals.aspx

Answer 8

\(\large\color{black}{ f(x)=\sqrt[3]{\frac{3x}{2}+\sqrt{\frac{x}{4}}} }\)

\(\large\color{black}{ f(x)=\sqrt[3]{\frac{3x}{2}+\frac{\sqrt{x}}{\sqrt{4}}} }\)

Answer 9

cool ty ill try to figure this out

Answer 10

\(\large\color{black}{ f(x)=\sqrt[3]{\frac{3x}{2}+\frac{\sqrt{x}}{2}} }\)

Answer 11

is that the most u can simplify it?

Answer 12

\(\LARGE\color{black}{ f(x)=\sqrt[3]{\frac{3x+\sqrt{x}}{2}} }\)

Answer 13

No...

Answer 14

\(\LARGE\color{black}{ f(x)=\frac{\sqrt[3]{3x+\sqrt{x}}}{\sqrt[3]{2} } }\)

Answer 15

\(\LARGE\color{black}{ f(x)=\frac{ \sqrt[3]{4} \times\sqrt[3]{3x+\sqrt{x}}}{\sqrt[3]{2} \times \sqrt[3]{4} } }\)

Answer 16

\(\LARGE\color{black}{ f(x)=\frac{ \sqrt[3]{4} \times\sqrt[3]{3x+\sqrt{x}}}{2 } }\)

Answer 17

DO YOU WANT THE ANSWER LOL

Answer 18

wait why did u multiply it by cube root 4 instead of 2?

Answer 19

Lol yes and how to do it xD

Answer 20

JK IDONT EVEN KNOW WHAT YOU TALKING ABOUT

Answer 21

I multiplied TOp and BOTTOM times cube root of 4, so i didn't change the value of the function...

Answer 22

Do you understand everything so far?

Answer 23

oooh okay i gotcha thanks

Answer 24

yea

Answer 25

no clue

Answer 26

\(\LARGE\color{black}{ f(x)=\frac{ \sqrt[3]{12x+4\sqrt{x}}}{2 } }\)

Answer 27

THANK YOU SO MUCH!!!

Answer 28

yes, you can turn the 2 on the bottom into a 1/2 coefficient up front. But there is no way to simplify it.

Answer 29

yw

Answer 30

kk thanks a ton

Answer 31

I mean it can alternatively look like \(\LARGE\color{black}{ f(x)=\frac{1}{2} \sqrt[3]{12x+4\sqrt{x}} }\) .

Answer 32

but it is either way a same thing.

Answer 33

You welcome once again:)

Answer 34

yeah i see, thanks once again xD