Question

16 - x^2

Answer 1

(16-x^2)-1
x^2-16
x=4 and x=-4

Answer 2

Use the limit process for integral {1,3] to evaluate

Answer 3

I don't know how this website works, I'm sorry.

Answer 4

\(\large\color{black}{x^2-16\color{red}{=0} }\) I am correcting your little mistake with red.

Answer 5

I mean the other way,
\(\large\color{black}{ 16-x^2=0 }\) but that doesn't matter, because x-solutions will either way be the same.

Answer 6

yes, \(\large\color{black}{ x=\pm4 }\) is correct.

Answer 7

I'm doing calculus haha, I need to use the limit process to find the area of the region [1,3]

Answer 8

What is the exact question?

Answer 9

you want
\[\Large \int\limits_{1}^{3} 16-x^2~~dx\]right?

Answer 10

yes!