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Mathematics 17 Online
OpenStudy (mendicant_bias):

Can an IVP have conditions imposed of the same order?

OpenStudy (mendicant_bias):

Like, if I had some given IVP, and my conditions were, \[y(0)=a, \ y(5)=b, \ y(3)=2;\]Is that even allowed in the first place? I know you can do that with a BVP, but I don't know about an IVP.

OpenStudy (mendicant_bias):

@Concentrationalizing @bloopman

OpenStudy (anonymous):

Yeah, sure, but I don't see how that's very useful or necessary anyway

OpenStudy (anonymous):

You only need one to complete an IVP

OpenStudy (anonymous):

Right, as long as you can find a solution that satisfies one of the initial conditions, the other unknown constant can be anything. So let's say you have a solution like \(y = c_{1}\cos(x) + c_{2}\sin(x),\ y(0) = 1, y(\frac{\pi}{2}) = 5\) Well, just plugging in the first initial condition, you'd get c1 = 1. That's all you need. You know that condition gives you a solution, so make c2 whatever you feel like, the solution will still satisfy the conditions.

OpenStudy (mendicant_bias):

Alright, thanks.

OpenStudy (anonymous):

Yw

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