Can an IVP have conditions imposed of the same order?
Like, if I had some given IVP, and my conditions were, \[y(0)=a, \ y(5)=b, \ y(3)=2;\]Is that even allowed in the first place? I know you can do that with a BVP, but I don't know about an IVP.
@Concentrationalizing @bloopman
Yeah, sure, but I don't see how that's very useful or necessary anyway
You only need one to complete an IVP
Right, as long as you can find a solution that satisfies one of the initial conditions, the other unknown constant can be anything. So let's say you have a solution like \(y = c_{1}\cos(x) + c_{2}\sin(x),\ y(0) = 1, y(\frac{\pi}{2}) = 5\) Well, just plugging in the first initial condition, you'd get c1 = 1. That's all you need. You know that condition gives you a solution, so make c2 whatever you feel like, the solution will still satisfy the conditions.
Alright, thanks.
Yw
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