Question

***Simple Nuclear Physics Question***

Answer 1

my attempt at #3) No=3.3g X 1mol/69.72g X 6.02e23 nuclei/mol=2.85e22nuclei.
so Ro=lambda*No=(.0089hrs-1/3600sec)(2.85e22nuclei)=7.036e16 nuclei/sec(or Bq)

Answer 2

Hint: Remember for first order decay:
-dA/dt = k[A]

you found k in part 2 and you were given A

Answer 3

Whats my A?

Answer 4

isn't A the No im solving for in my equation? @surry99

Answer 5

nvm I figured it out. My mistake was using the atomic mass for Ga(69.72g/mol), when I was given a Ga-67(66.93g/mol).

Answer 6

good stuff