Question

Can someone show me how to do this log2(x+1)-log4(x)=1

Answer 1

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Answer 2

I will tag some users that may be able to help you with this. @Compassionate @jigglypuff314 @Nnesha

Answer 3

\(\large\color{black}{ \log_2(x+1)-\log_4(x)=1 }\)
\(\large\color{black}{ \log_2(x+1)-\log_4(x)=\log_44 }\)
\(\large\color{black}{ \log_2(x+1)=\log_44+\log_4(x) }\)
\(\large\color{black}{ \log_2(x+1)=\log_4(4x) }\)

\(\LARGE\color{black}{ \log_{2}(x+1)= \frac{\log_{2}4x}{\log_{2}4} }\)

Answer 4

See what I am doing? Can you continue from here, or need more help?

Answer 5

but the asker is not any more-:(

Answer 6

My approach is fairly simple though, isn't it? Anyway, tnx for the medal, and I guess this is another time.....

Answer 7

Lol, nice glitch:)

Answer 8

you m :P jk

Answer 9

Wait what? http://prntscr.com/5eezsn

Answer 10

yes something wrong with this site

Answer 11

Latex disconnected me from the site, not an internet issue. This has been a trouble for all of my OpenStudy career, so to speak.

Answer 12

I see it fine....

Answer 13

that is your view.... :P

Answer 14

meals doesn't like you :P :P: P

Answer 15

lol

Answer 16

jk