Question

Choose the correct answer:


C4H10 + Br2 -inDirect sun light-> C4H9Br + HBr

1- CH3-CH2-CH2-CH2Br
2- CH3-CH2-CHBr-CH3

Answer 1

It is 1, because during this reaction, the halogen at first has to attack one of the ends of the hydrocarbon.

Answer 2

According to which rule , I am really confused because of Marconikov.

Answer 3

This is completely different from MarkovNikov. When you add a nucleophile, like HBr, you use his rule, in which the halogen goes to the least hydrogenated carbon in the double bond, wherear in a free radical substitution, it happens what I said previously. Plus, MarkovNikov's arule applies to addition reaction, which occurs in compounds with double bonds or triple bonds and alkanes do not undergo such reactions, because only have single bonds. They undergo free radical substitution. That is the thing about alkanes - substitution reactions only.

Answer 4

Thanks for your time and valuable information.

Answer 5

No problem, for further question do not hesitate to ask.