Question

i just need help with a, c, and d

Answer 1

sorry, the previous one had a c = -102 not -112. My arithmetic error!

Answer 2

its okay! I ended up getting it :) this one is racking my brain though: i haven't taken physics yet :/

Answer 3

How did you get the first answer, and pay attention to the units.

Answer 4

my first answer was wrong and I asked a person on here and they told me that that was the answer because its velocity's derivative so from 16^2 or whatever it'd be 32 ft/s^2

Answer 5

Oh I see, 32ft/s^2 is the acceleration of gravity, I forget some people still don't use SI units.

Answer 6

yeah… so idk what to do with the problem… haven't taken physics

Answer 7

Ok so that's right, mhm I wonder, have you tried -32 ft/s^2

Answer 8

yep :/ that was my first guess

Answer 9

Could it be the decimal points/ number of significant digits?

Answer 10

Is that the full question

Answer 11

yes thats the full question.. :/ it had me stumped. then i though it could have been -32t +

Answer 12

244

Answer 13

but that was wrong as well

Answer 14

No, the surface of the earth has the acceleration due to gravity, a(t) = - g, so |-g| = 32 ft/s^2

Answer 15

i still dont know what i'd put as the solution though because i tried that and it was incorrect :/

Answer 16

244? Your velocity is 224

Answer 17

yeah i tried that as well; I even tried -244 lol

Answer 18

iambatman should quit wasting peoples time and if he don't know don't give your so called "help"

Answer 19

I have it but now since you made another account to insult, good luck finding the solution yourself, I'll give you one hint though: Kinematic formulas. Use it.

Answer 20

it aint another account to insult just stating facts

Answer 21

if you really wanted to know I'm here friend

Answer 22

her

Answer 23

IP checks don't lie, in any case, good luck, I've gave you a hint and if you just want the answer, you shouldn't be here.

Answer 24

I appreciate your help. I'm sorry for my absence; I was working on other homework. Also, I did not mean for any insults to take place tonight. I am grateful for any help received on here and believe everyone to be greatly appreciated.

Answer 25

Once again, thank you and have a good night.

Answer 26

Well if you'd like to fully understand this problem, first list off what the knowns and unknowns are, and there are some neat kinematic formulas that will help you with this specific question.

So what is the final velocity, initial velocity, etc and what do you have?

Answer 27

Another hint: \[v = v_o+at\]

Answer 28

i figured out by looking at the function you told me to look at :) I ended up graphing a function finding where it was maximized and minimized, then simply found the area under the curve. so thank you! I wouldn't have figured it out without your hint

Answer 29

Alright, well so what assumptions can be made for part (a)? Given the information we have now.