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Mathematics 15 Online
OpenStudy (anonymous):

Find the total surface area of this object. *picture in comments*

OpenStudy (anonymous):

OpenStudy (anonymous):

find the surface area of the big square (l * l), the surface area of the 2 triangle (1/2*b*h) and the area of the rectangle (l*w), add them together

OpenStudy (anonymous):

1/2*b*h multiply by 2 for both triangles

OpenStudy (anonymous):

Okay, one sec

OpenStudy (anonymous):

Is the area of the big square 40? and the area of the two triangles 6? I feel like I'm way off.

OpenStudy (anonymous):

the area of each triangle is 1/2(b*h) or 1/2(3*4)

OpenStudy (anonymous):

then use the pythagorean theorem to find the side of the big rectangle (sorry I meant rectangle not square)

OpenStudy (anonymous):

so 10* (sqrt(3^2 + 4^2))

OpenStudy (anonymous):

is the area of the big square

OpenStudy (anonymous):

rectangle*

OpenStudy (anonymous):

then the area of the small rectangle is just 10 * 3

OpenStudy (anonymous):

So 30 for the small rectangle. Big square is 100? and I got 12 for triangles.

OpenStudy (anonymous):

no big rectangle is 10* (sqrt(3^2 + 4^2))

OpenStudy (anonymous):

correct, each triangle is 6 so both triangles is 12

OpenStudy (anonymous):

so 12 + 30 + 10* (sqrt(3^2 + 4^2))

OpenStudy (anonymous):

so 12 + 30 + (10* (sqrt(3^2 + 4^2)))

OpenStudy (anonymous):

is it 92? Because It says that is wrong when I type that in?

OpenStudy (anonymous):

oops forgot about the base area, which is 10* 4

OpenStudy (anonymous):

so 92 + 40

OpenStudy (anonymous):

There we go. Thanks a lot!

OpenStudy (anonymous):

nice :)

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