Question

find the fifth term of the sequence which has a first term of 17 and a common ratio of 3.1

Answer 1

@jordanloveangel

Answer 2

sorry i took long time

Answer 3

A{1} = 17 ; and a geometric ratio o f 3.1

A{2} = 17 * 3.1

A{3} = 17 * (3.1 * 3.1)

A{4} = 17 * (3.1 * 3.1 * 3.1); [3.1^3]

A{n} = 17 * 3.1^(n-1)

A{5} = 17 * 3.1^(4)

I get 1569.98... if i did it right

Answer 4

It's alright.
Thank you omg.

Answer 5

lol np

Answer 6

That wasn't right, but I can probably get my mom to help. Thanks for attempting to help though.

Answer 7

np sorry i tryed

Answer 8

It's alright.

Answer 9

@Catlover5925

Answer 10

ok so multiply # by 3 17 * 3 is 51 so it is a 3:1 ration
so it would be 17, 51, 153, 459, 1377.....i think this is correct

Answer 11

does this make sense?? @jxss.xca

Answer 12

Yeah. Thanks.