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log3(256)/log3(2)=?
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this is the change of base formula
\[\frac{ \log _{3} (256) }{ \log _{3} (2)} \]
it is the same as \[\log_2(256)\]which you solve via \[2^x=256\]
how did you get log2(256)? @satellite73
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\[\frac{ \int\limits_{1}^{256}\frac{ 1 }{ t } dt }{ \int\limits_{1}^{2}\frac{ 1 }{ t } dt}\]
\[\frac{ \frac{ \log (256) }{ \log (3) \log (2) } }{ \log (3) }\]
so what do you think is the result, @lol09lune
\[8\]
hope this all helped
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