Question

Which is the equation of the line that contains points (8,10) and (-4,2)?
Y-10=3/2(x-8)
Y-8=3/2(x-10)
Y-10=2/3(x-8)
Y-8=2/3(x-10)
*help I suck at math :(

Answer 1

What do you think the answer is?

Answer 2

you know how to find the slope?

Answer 3

I have no idea how to do any of this ._.!

Answer 4

(8,10) and (-4,2)
\[m=\frac{y_2-y_1}{x_2-x_1}\] which in your case is
\[\frac{10-2}{8-(-4)}\]as a first step

Answer 5

compute this fraction get
\[\frac{8}{12}\]which reduces to \(\frac{2}{3}\)

Answer 6

Well we know that if a point is on the line, then it will satisfy the equation. So for your points (8,10) and (-4,2), you have two methods of solving this:

1. Sub in these values of x and y into each of the four equations and see which is the only one that works.
2. Rearrange the four equations so they are of the form y=mx+c, then calculate the line between these points and see which one of the four it matches.

Take your pick! Personally, I think the first approach is easiest for this question.

Answer 7

that eliminates the first two choices

Answer 8

then the "point slope" formula is
\[y=y_1=m(x-x_1)\] if you use the point \((8,10)\) and \(m=\frac{2}{3}\)you get
\[y-10=\frac{2}{3}(x-8)\]

Answer 9

Ok so I'm a try and work it out and see what I get :)

Answer 10

you are not actually being asked to put in the slope intercept form, just the point slope form

so you are done at that step

Answer 11

Oh if see ! Thank you :)