find derivative of y=sin(x)^tan(x)
\[y=\sin(x)^{\tan(x)}\]
logarithmic pls
tan(x)ln(sin(x))
product rule
ya thats the approach i took first but
ehehhehhehe
u can continue jhan
my teacher showed us how to do it a different way but i dont remember
Then go by what you know, not what your teacher has taught you, that's his method of solving it. when it comes to the test you're not trying to remember his methods but how you're most comfortable solving the problem in time
Haha :P
i entered it in on mathway and got a different answer
Well, what do you get when you use the product rule on \(\tan(x)\ln(\sin(x))\)?
tan(x)cot(x)+sec^2(x)ln(sin(x))
or something like that i think
then its y'/y=that
\[d(\tan(x)\ln(\sin(x))) = \sec^2(x)\cdot \ln(\sin(x)) +\frac{1}{\sin(x)}\cdot \cos(x) \cdot \tan(x) \]
Yeah, you're right.
but if you go on mathway and do it u get some really long crazy answer
that involves e
Hmm dunno.
theres one more problem i need help with ill create a new question
Join our real-time social learning platform and learn together with your friends!