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Mathematics 18 Online
OpenStudy (tylerd):

find derivative of y=sin(x)^tan(x)

OpenStudy (tylerd):

\[y=\sin(x)^{\tan(x)}\]

OpenStudy (mimi_x3):

logarithmic pls

OpenStudy (mimi_x3):

tan(x)ln(sin(x))

OpenStudy (mimi_x3):

product rule

OpenStudy (tylerd):

ya thats the approach i took first but

OpenStudy (mimi_x3):

ehehhehhehe

OpenStudy (mimi_x3):

u can continue jhan

OpenStudy (tylerd):

my teacher showed us how to do it a different way but i dont remember

OpenStudy (jhannybean):

Then go by what you know, not what your teacher has taught you, that's his method of solving it. when it comes to the test you're not trying to remember his methods but how you're most comfortable solving the problem in time

OpenStudy (jhannybean):

Haha :P

OpenStudy (tylerd):

i entered it in on mathway and got a different answer

OpenStudy (jhannybean):

Well, what do you get when you use the product rule on \(\tan(x)\ln(\sin(x))\)?

OpenStudy (tylerd):

tan(x)cot(x)+sec^2(x)ln(sin(x))

OpenStudy (tylerd):

or something like that i think

OpenStudy (tylerd):

then its y'/y=that

OpenStudy (jhannybean):

\[d(\tan(x)\ln(\sin(x))) = \sec^2(x)\cdot \ln(\sin(x)) +\frac{1}{\sin(x)}\cdot \cos(x) \cdot \tan(x) \]

OpenStudy (jhannybean):

Yeah, you're right.

OpenStudy (tylerd):

but if you go on mathway and do it u get some really long crazy answer

OpenStudy (tylerd):

that involves e

OpenStudy (jhannybean):

Hmm dunno.

OpenStudy (tylerd):

theres one more problem i need help with ill create a new question

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