Question

Find an equation of the circle whose diameter has endpoints (5,3) and (−3,1).

Answer 1

The radius will be half the distance between these points. The center will be the midpoint.

Answer 2

Once you get the radius \(r\) and the center \((h,k)\), then your equation is: \[
(x-h)^2+(y-k)^2=r^2
\]

Answer 3

So would the center points = (1,2)?

x= (5-3)/2 and y = (3+1)/2?

Then use the radius formula \[\sqrt{(x2-x1)^{2}+(y 2-y1)^{2}}\] ?

Or am I missing something

Answer 4

correct