Ask your own question, for FREE!
Algebra 16 Online
OpenStudy (ironhide):

If I could give you a million medals I would. Can someone PLEASE help me with this? I don't understand how to do it. http://o.aolcdn.com/hss/storage/fss/ef67e9b00d5865fc9dadb5c2ce15a30/Screenshot+2014-12-10+01.25.27.png

OpenStudy (anonymous):

Alright then! When an interval is given with closed square brackets it means the values are included. All you have to simply do is in each equation with its given interval, replace x with the smallest and greatest values given in their respective intervals. Once you find the 2 values of f(x) for each function, one will be the smallest and the other the greatest and finally compare them all in terms of their magnitude.

OpenStudy (anonymous):

Understood? Should I solve a bit?

OpenStudy (ironhide):

Ahh... Kind of? Would you be able to solve just one and explain so maybe I can grasp what to do for the others?

OpenStudy (anonymous):

Of course.

OpenStudy (anonymous):

Let us go for the first function. x+4 Using x as 4, f(x)= 4+4=8 Using x as 5, f(x)=5+4=9 Find the average of the function is 8+9/2= 8.5 So basically you find the two values of f(x) and average them. In the end place them in ascending order. Got ot?

OpenStudy (ironhide):

Okay, so for the second one, f(x)=3x-7 over [-3, 7] f(x)=(3)-3-7= -16 f(x)=(7)-3-7= -28 -16-28= -44 -44/2= -22?

OpenStudy (anonymous):

No. For the second f(x) is 3(7)-7=14

OpenStudy (anonymous):

Not -7, but +7. Look at the interval properly.

OpenStudy (anonymous):

Got it?

OpenStudy (ironhide):

OOPS when I was writing down first from my screen to my paper, and then back to the computer on here, I mixed those all up. BUT, disregarding my messup with the symbols, did I do the problem correctly?

OpenStudy (ironhide):

The steps/how to solve?

OpenStudy (anonymous):

Yes.

OpenStudy (ironhide):

THANK YOU SO MUCH. It was so much simpler than my online class made it seem. Thank you for explaining it so simply and quickly. Wow. Also, I redid that last one and I see that it's -1 now :)

OpenStudy (anonymous):

Good.

OpenStudy (ironhide):

One last thing... If you have a table, and it's columns are x and f(x) how do you input that over an interval?

OpenStudy (ironhide):

like , for example rate of change over the interval [-3, 4] x | f(x) -6 | 27

OpenStudy (anonymous):

You can put in your title the function and the interval THen in your table,myou place your least and greatest values of x in a collumn and f (x) values in rows.

OpenStudy (anonymous):

I think it is up to you to choose organization.

OpenStudy (ironhide):

Well, it asks to find the rate of change, like the last problem, not to make the table itself. I don't understand how you find the rate of change over an interval when it's just coming off of a graph.

OpenStudy (ironhide):

a table** not graph, sorry

OpenStudy (anonymous):

From what I remember, he rate of change of a function is the first derivate of it. FOR Example for ther function 3x-7, its rate of change is 3 units /s.

OpenStudy (ironhide):

When it's on the table though, how do you know how to lay it out like that though? Like in the example I gave, is it f(x)=-6x-27? I don't know. Ahhh I'm sorry

OpenStudy (anonymous):

What ? No problem. We are here for that. Okay. Imagine you are planing in doing a table for each function. IF THIS IS THE case, write the function and the respective interval as the title and on your first row and first collumn write x and on the second column and first row write f(x) and in the entire x row write the x intervals and below the f(x) write the answers obtained when you replace x in the formula.

OpenStudy (ironhide):

I think I confused you. I'm not explaining correctly, this is my fault I apologize. I'll give you a screenshot of what the question is asking.

OpenStudy (ironhide):

OpenStudy (anonymous):

For this one i am not sure, but what I would do was sum the value of f(x) for the least and greates value of x and divide by 5 since in your table there are 5 values of that interval, I would get 6.6

OpenStudy (ironhide):

Okay, I will do that. Thank you for all of your help. I'm really grateful!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!