Question

ok

Answer 1

What are you solving?

\((x*y)(x*y)=x*x*y*=x^2y^2\)

Answer 2

polynomial identites and proofs

Answer 3

(x*y)(x*y)
x^2 + xy + yx + y^2

Hmm... Simplify

Answer 4

Solve as in multiply? It's not an equation so you can't solve for anything

Answer 5

Not much to do, it's multiplication so you can multiply in any order.
So you can group x's with x's and y's with y's
What would x*x be?

Answer 6

$$\large\text{(x*y)(x*y)}$$$$\large\text{ = (y*x)(x*y) ___commutative prop. of mult}$$$$\large\text{=y*x(x*y) _____unnecessary ( ) }$$$$\large\text{=y*(xx)*y _____associative prop. of mult.}$$$$\large\text{=y*(x^2)*y ____definition of a power}$$$$\large\text{=y*y*(x^2) ____commutative prop. of mult}$$$$\large\text{ =y^2*x^2 ____definition of a power }$$

Answer 7

can you guys see if I'm solving this right?