Question

THE ALGEBRA OF SUMMATION NOTATION Question

Answer 1

\[\sum_{i=0}^{3}(5\sqrt{4^i}\]

Answer 2

5 times a geometric sumation

Answer 3

do we recall the formula for a geometric sum?

Answer 4

So that means it equals \[=(5+\sqrt{4^1})+(5+\sqrt{4^2})+(5+\sqrt{4^3})\]

Answer 5

correct

Answer 6

Is that the final answer, or does it need to be simplified more?

Answer 7

Because once i got further in i got

\[(5\sqrt{1})+(5\sqrt{16})+(5\sqrt{})+\]

Answer 8

depends on what the question is calling for i spose

Answer 9

It asked me to Evaluate it

Answer 10

So once i got \[(5\sqrt{1})+(5\sqrt{16})+(5\sqrt{64})\] Do i simplify that, or keep it as it is?

Answer 11

5(4) + [ sqrt(1) + sqrt(4) + sqrt(4.4) + sqrt(4.4.4)]

20 + [ 1 + 2 + 2^2 + 2^3]

Answer 12

So I should do the following:\[(5+2)+(5+4)+(5+8)\]

Answer 13

not 5(4) ..... brain slip

\[\sum_{i=0}^35\sqrt{4^i}\]
\[5\sum_{i=0}^3\sqrt{4^i}\]
\[5(\sqrt{4^0}+\sqrt{4^1}+\sqrt{4^2}+\sqrt{4^3})\]

Answer 14

5(1+2+4+8)

5(3+12)

5(15)

Answer 15

5^4 :)

Answer 16

Thanks @amistre64 I understand it better now. The way their telling me is much more difficult to comprehend.