MEDAL GIVEN!!!! Rationalize the denominator of sqrt 5 / 6+sqrt2
multiply times the conjugate.
\[\frac{ \sqrt{5} }{ 6+\sqrt{2} }\]
to rationalize the denominator, you always multiply by the conjugate
What is the conjugate
\[\frac{ \sqrt{5} }{ 6+\sqrt{2} }*\frac{ 6-\sqrt{2}}{ 6-\sqrt{2} }\]
So then we minus
the conjugate is when you take the term you have and change the sign sign in the middle as the simplest explanation I can give you. here we have\[6+\sqrt{2}\] so the conjugate is\[6-\sqrt{2}\]
if we had \[8-\sqrt{13}\] the conjugate would be \[8+\sqrt{13}\]
Okay so then what do I do
you multiply the top and bottom by the conjugate
use the foil method to get your answer
4.5
are you asked to give an exact answer or just to rationalize and then leave it?
Simplify the answer
A. -2sqrt5 - sqrt30 / 2 B. 6sqrt5-sqrt10/34 C. 6sqrt5-sqrt10/31 D. 5sqrt5 - sqrt12 /23
well lets multiply it out\[\frac{ 6\sqrt{5}-\sqrt{10} }{ 36-6\sqrt{2}+6\sqrt{2}-\sqrt{2}^{2} }\]
we cant simplify the top anymore and the 6sqrt2 on the bottom cancel
Okay would b be the closet answer
sqrt2^2 equal 2 so we have\[\frac{ 6\sqrt{5}-\sqrt{10} }{ 36-2 }\]\[\frac{ 6\sqrt{5}-\sqrt{10} }{ 34 }\]
Thank you!!!!
plugging that into our handy dandy calculator we get a 0.302
you are welcome
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