Question

this fraction: (a^2-5)/(a^3-1) minus this fraction (a+1)/(a^2+a+1)
a. (-4)/(a^3-1)
b. (-6)/(a^3-1)
c. (a^2-a-6)/(2a)
^^^^^^^^^^^^^^^^ all of these are fractions

Answer 1

If this helps, this is the problem

Answer 2

well you need a common denominattor

the factored form is the denominator in the 1st fraction is

a^3 -1 = (a -1)(a^2 + a + 1)

this is the difference of 2 cubes

Then multiply the numerator and denominator of the 2nd fraction by (a - 1)

which would give

\[\frac{a^2 - 5}{(a - 1)(a^2 + a + 1} - \frac{(a + 1)(a -1)}{(a-1)(a^2 + a + 1)}\]

now simplify it by collecting like terms in the numerator

Answer 3

lookin at the answers you will need to rewrite the denominator as the difference of 2 cubes

that is

a^3 - 1

Answer 4

Thank you @campbell_st

Answer 5

I got the first answer.

Answer 6

that's what I got