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OpenStudy (phi):
can you write 4 2/7 as an improper fraction ?
OpenStudy (anonymous):
its 30/7
OpenStudy (phi):
yes. now do the same for 2 1/5
OpenStudy (anonymous):
11/5
OpenStudy (phi):
now you have
\[ \frac{30}{7}\cdot \frac{11}{5} \]
you multiply top times top and bottom times bottom
BUT... it's simpler to first look for numbers that you can simplify.
notice 30 can be divided by 5 and 5 (in the bottom) can be divided by 5
so do that:
\[ \frac{\cancel{30}6}{7}\cdot \frac{11}{\cancel{5}1} \]
now do top times top and bottom times bottom
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OpenStudy (anonymous):
ok thanks :)
OpenStudy (phi):
what do you get ?
OpenStudy (anonymous):
1 sec
OpenStudy (anonymous):
66/7
OpenStudy (phi):
now change back to a whole number plus a fraction.
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OpenStudy (anonymous):
that would be 9 and something over umm7
OpenStudy (phi):
the remainder over the divisor (i.e over 7)
you can check your answer by changing it back into an improper fraction .. if you did it correctly, you get back 66/7
OpenStudy (anonymous):
ya i know that the answer is 9 and something over 7 but i cant get that part cuz i dont know how
OpenStudy (phi):
7 goes into 66 9 times
7*9= ?
OpenStudy (anonymous):
63
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OpenStudy (phi):
yes.
Here is how you divide:
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