Assume that a helicopter is landing perpendicular to you at a constant distance x away from you. In the triangle below, h(t) is the height of the helicopter. Assume that the derivative of h with respect to t, is how quickly the helicopter is approaching the ground. When the helicopter is h miles high, what is the rate of change of θ?

Question

anonymous · Answer

A: the derivative of theta with respect to t equals negative h over the quantity h squared plus x squared times the derivative of h with respect to t
		
B: the derivative of theta with respect to t equals x over the quantity h squared plus x squared times the derivative of h with respect to t
		
C: the derivative of theta with respect to t equals the opposite of h squared over the quantity h squared plus x squared times the derivative of h with respect to t
		
D: the derivative of theta with respect to t equals x squared over the quantity h squared plus x squared times the derivative of h with respect to t

anonymous · Answer

I believe the answer to be A myself, but I'd like confirmation.