Question

Simplify : sin(x)+cot(x)cos(x)

Answer 1

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@Jhannybean @zepdrix

Answer 2

Hint:\[\cot(x) = \frac{\cos(x)}{\sin(x)}\]

Answer 3

is it 1 ? or 2

Answer 4

\[\sin(x)+[\frac{\cos(x)}{\sin(x)}]\cos(x) ---->\sin(x)+\frac{\cos(x)^2}{\sin(x)}\]

Answer 5

no you just simplify.

Answer 6

\[\frac{\sin^2(x)}{\sin(x)}+\frac{\cos^2(x)}{\sin(x)}\]

Answer 7

\[\frac{\sin^2(x)+\cos^2(x)}{\sin(x)}\]

Answer 8

\[\frac{1}{\sin(x)}\]

Answer 9

csc(x)

Answer 10

Do you understand?

Answer 11

i thought it would be 1 since you just cross out

Answer 12

Basically,
\(\large\color{black}{ \sin(x) + \cot(x) \cos(x) }\)

\(\large\color{black}{ \sin(x) + \frac{\LARGE\cos(x) }{\LARGE\sin(x)} \cos(x) }\)

\(\large\color{black}{ \sin(x) + \frac{\LARGE\cos^2(x) }{\LARGE\sin(x)} }\)

\(\large\color{black}{ \frac{\LARGE\sin^2(x) }{\LARGE\sin(x)} + \frac{\LARGE\cos^2(x) }{\LARGE\sin(x)} }\)

\(\large\color{black}{ \frac{\LARGE\sin^2(x)+\cos^2(x) }{\LARGE\sin(x)} }\)

\(\large\color{black}{ \frac{\LARGE1 }{\LARGE\sin(x)} }\)

Answer 13

If you have a question regarding any of the steps, ask.

Answer 14

Be careful with cotangent; it is not the same as tangent, so canceling doesn't occur

Answer 15

Wait, what?

Answer 16

no body canceled anything, .... have I? :)

Answer 17

No, the OP assumed a canceling out which isn't there

Answer 18

We agree on the\[\frac{1}{\sin(x)}\]

Answer 19

Which can also be called csc(x)

Answer 20

thank you

Answer 21

Simplify: cot(x)sin(x)sec(x)=