Question

@Cuanchi with calculate the amount of energy in joules required to change 10 grams of solid mercury at its melting point to mercury vapor at the boiling pt. the melting point, boiling point and specific heat capacity are -39C 375C and 0.140 J/gC, respectively. heat of fusion= 11.4 J/g heat of vaporization; 295 J/g. Compare with amount of heat needed to change 10 grams of ice at 0C to steam @100C

Answer 1

@Cuanchi ppplz

Answer 2

@Abhisar cant do this problem

Answer 3

@ganeshie8 help pplz

Answer 4

@lesliejcastorena help me

Answer 5

@iamabatman help me

Answer 6

@adamaero help me

Answer 7

@sleepyjess i need help

Answer 8

@sleepyjess u know how to do it

Answer 9

@pplz idek how to do it

Answer 10

@jfraser i need help

Answer 11

@abmon98 i need help

Answer 12

@chvmijay i need help NOW

Answer 13

@ganeshie8

Answer 14

E=m Ce delta T
you have to calculate the energy of the 10 g of Hg(s) to became liquid
E1= 10g x11.4J/g=
then the energy to heat it up the 10 g of Hg from -39C to 295C
E2= m Ce delta T =10g x 0.140J/g x (295+39)=
then the energy to convert the Hg(l) to gas
E3= 10g x 295 J/g=

finally you add E1+E2+E3

do the same for the water look in tables the heat of fusion and vaporization and Ce for H2O