For the picture attached inside, during what time interval does vy become zero? 0-1 s, 1-2 s, 2-3 s, or never ? not sure how to interpret the image!! :( thank you!!!
vy is the vertical component of the velocity. As the cannonball leaves the cannon, it has a positive vertical component. The cannonball is moving up. When it reaches the top, the vertical velocity is zero. Then as the ball starts to fall, the vertical velocity becomes negative.
ohh, so would the top be where the 1 s is located? if so, would that mean that vy becomes zero i the interval of 0-1 s ? @mathstudent55 :)
*zero in the
The question is during which interval does the vertical component become zero. Look at the figure. Where is the highest point of the path located? Between 0-1, 1-2, 2-3?
From the way I'm looking at the picture, I would say it reaches the top slightly after the 1s mark
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