Question

Identify the 31st term of an arithmetic sequence where a1 = 26 and a22 = -226

Answer 1

use \[a _{n}=a _{1}+\left( n-1 \right)d\]
find d
and then \[a _{31}\]

Answer 2

so? a22=26+(22-1)d

Answer 3

correct.

Answer 4

so a22=26+(21)d

Answer 5

then what? add 26+(21)?

Answer 6

-226=26+21 d

Answer 7

find d

Answer 8

-273?

Answer 9

21 d=-226-26=-252
d=-252/26

Answer 10

-9.69....

Answer 11

d=-126/13
find \[a _{31}\]

Answer 12

I am so lost now

Answer 13

it is simplification only.

Answer 14

got the answer. -334 thanks

Answer 15

\[a _{31}=26+(31-1)\times \frac{ -126 }{ 13 }\]
there is something wrong either in your calculations or in statement.

Answer 16

sorry ,i am leaving now.